How do you solve $36^(x+2 )= 6^(3x-3)$ ?

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Answer 1 · 2015-07-22T16:01:29

$color(blue)(x=7$

$36^(x+2) = 6^(3x-3)$

$36=6^2$

The expression becomes:

$6^(2*(x+2)) = 6^(3x-3)$

$6^(2x+4)= 6^(3x-3)$

Now, since the bases are equal, we equate their respective powers:

$2x+4 = 3x-3$

$x = 4+3$

$color(blue)(x=7$

How do you solve 36^(x+2 )= 6^(3x-3)36^(x+2 )= 6^(3x-3)?