How do you solve $36^ (x + 2) = 6 ^(4x)$ ?

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Answer 1 · 2016-04-05T05:19:59

$x=2$

$1$ . Knowing that $36=6^2$ , simplify $36^(x+2)$ .

$36^(x+2)=6^(4x)$

$6^(2(x+2))=6^(4x)$

$6^(2x+4)=6^(4x)$

$2$ . Since the powers both have the same base on either side of the equation, the exponents are equal to each other.

$2x+4=4x$

$3$ . Solve for $x$ .

$2x=4$

$color(green)(|bar(ul(color(white)(a/a)x=2color(white)(a/a)| )))$

How do you solve 36^ (x + 2) = 6 ^(4x) 36^ (x + 2) = 6 ^(4x) ?