How do you solve $3ln(x-3)+4=5$ ?

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Answer 1 · 2015-10-01T14:41:43

$x = root(3)(e) + 3$

Isolate the log

$3ln(x-3) = 5-4$
$ln(x-3) = 1/3$

Take the exponential from both sides, i.e.: the sideth power of e

$x-3 = e^(1/3) = root(3)(e)$

Isolate x

$x = root(3)(e) + 3$

How do you solve 3ln(x-3)+4=53ln(x-3)+4=5?