How do you solve $3log_3 4a=3$ ?

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Answer 1 · 2016-06-09T01:05:22

$log_3(4a)^3 = 3$

Use the rule $alogn = logn^a$

$log_3(64a^3) = 3$

Recall that if $log_a(n) = x$ , then $a^x = n$

$64a^3 = 27$

$a^3 = 27/64$

$a = root(3)(27/64)$

$a = 3/4$

Hopefully this helps!

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