How do you solve #(3x-1)^2=(2x+3)^2#? Algebra Polynomials and Factoring Zero Product Principle 1 Answer Barney V. Apr 26, 2017 #color(blue)(x=4# Explanation: #(3x-1)^2=(2x+3)^2# square L.H.S. and R.H.S. #:.sqrt((3x-1)^2)=sqrt((2x+3)^2)# #:.sqrt((3x-1)(3x-1))=3x-1# #:.sqrt((2x+3)(2x+3))=2x+3# #:.3x-1=2x+3# #:.3x-2x=3+1# #:.color(blue)(x=4# check: substitute #color(blue)(x=4# #:.(3(color(blue)4)-1)^2=(2(color(blue)4)+3)^2# #:.11^2=11^2# Answer link Related questions What is the Zero Product Principle? How to use the zero product principle to find the value of x? How do you solve the polynomial #10x^3-5x^2=0#? Can you apply the zero product property in the problem #(x+6)+(3x-1)=0#? How do you solve the polynomial #24x^2-4x=0#? How do you use the zero product property to solve #(x-5)(2x+7)(3x-4)=0#? How do you factor and solve #b^2-\frac{5}{3b}=0#? Why does the zero product property work? How do you solve #(x - 12)(5x - 13) = 0#? How do you solve #(2u+7)(3u-1)=0#? See all questions in Zero Product Principle Impact of this question 4266 views around the world You can reuse this answer Creative Commons License