How do you solve #(3x+1)^2+(4x-3)^2=(5x-1)^2#?
1 Answer
Apr 26, 2017
Explanation:
Given:
#(3x+1)^2+(4x-3)^2=(5x-1)^2#
Multiply out both sides to get:
#9x^2+6x+1+16x^2-24x+9=25x^2-10x+1#
Simplifying the left hand side, this becomes:
#color(red)(cancel(color(black)(25x^2)))-18x+10 = color(red)(cancel(color(black)(25x^2)))-10x+1#
Add
#9=8x#
Divide both sides by
#x = 9/8#