Question

How do you solve `3x^2 - 10 = 2x` by completing the square?

Answer 1

1. Move the constant to the right
2. Make a = 1
3. Add on `(b/2)^2` to both sides
4. Write as (x +- b/2)^2 =
5. Find square toot of both sides
6. Solve twice - pos and neg square root

`3x^2 - 10 = 2x rArr 3x^2 - 2x = 10`

`x^2 - (2x)/3 + color(red)((1/3)^2) = 10/3 + color(red)((1/3)^2)`
`(x - 1/3)^2 = 31/9`

`x - 1/3 = +-sqrt31/3`

`x = sqrt31/3 + 1/3 " or " x = -sqrt31/3 + 1/3`

`x = 2.189 or x = -1.523`