How do you solve $3 x^{2} + 20 x + 36 = 4$ $3x^2 + 20x + 36 = 4$ by completing the square?

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How do you solve $3 x^{2} + 20 x + 36 = 4$ $3x^2 + 20x + 36 = 4$ by completing the square?

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Answer 1 · 2015-05-07T15:14:22

Let's solve your equation step-by-step.
$3 x^{2} + 20 x + 36 = 4$ $3x^2+20x+36=4$
Step 1: Subtract 4 from both sides.
$3 x^{2} + 20 x + 36 - 4 = 4 - 4$ $3x^2+20x+36−4=4−4$
$3 x^{2} + 20 x + 32 = 0$ $3x^2+20x+32=0$
Step 2: Factor left side of equation.
$(3 x + 8) (x + 4) = 0$ $(3x+8)(x+4)=0$
Step 3: Set factors equal to 0.
$3 x + 8 = 0 or x + 4 = 0$ $3x+8=0 or x+4=0$
$x = - \frac{8}{3} or x = - 4$ $x=−8/3 or x=−4$

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How do you solve $3 x^{2} + 20 x + 36 = 4$ $3x^2 + 20x + 36 = 4$ by completing the square?

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