How do you solve $-3x^2+24x=27$ by completing the square?

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Answer 1 · 2016-07-30T15:37:32

$x = 4 +- sqrt7$

Divide both sides by -3
$x^2 - 8x = -9$
$x^2 - 8x + 16 = -9 + 16 = 7$
$(x - 4)^2 = 7$
$(x - 4) = +- sqrt7$
$x = 4 +- sqrt7$

How do you solve -3x^2+24x=27-3x^2+24x=27 by completing the square?