How do you solve #-3x^2+26x=16#?

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Answer 1 · 2017-02-13T22:58:17

The roots of the quadratic are 0.67 and 8

Start by rearranging the equation into the standard form

#-3x^2 + 26x -16 = 0#

Using the quadratic formula #(-b +- sqrt(b^2 - 4ac))/(2a)#

substitute in the values from the equation
#(-26 +- sqrt(26^2 - 4*-3*-16))/(2*-3)#

Simplifying
#(-26 +- sqrt(676- 192))/-6#

#(-26 +- 22)/-6#

Using the positive discriminant (+22) the root is 0.67
Using the negative discriminant (-22), the root is 8