How do you solve #-3x^2+5x=-2#?
1 Answer
May 11, 2018
Explanation:
#"express in standard form "color(white)(x)ax^2+bx+c=0#
#"add 2 to both sides"#
#rArr-3x^2+5x+2=0#
#"multiply through by "-1#
#rArr3x^2-5x-2=0#
#"using the a-c method to factor"#
#"the factors of the product "3xx-2=-6#
#"which sum to - 5 are - 6 and + 1"#
#"split the middle term using these factors"#
#3x^2-6x+x-2=0larrcolor(blue)"factor by grouping"#
#color(red)(3x)(x-2)color(red)(+1)(x-2)=0#
#"take out the "color(blue)"common factor "(x-2)#
#rArr(x-2)(color(red)(3x+1))=0#
#"equate each factor to zero and solve for x"#
#3x+1=0rArrx=-1/3#
#x-2=0rArrx=2#