How do you solve 3x^2+5x=23x2+5x=2 by completing the square?

1 Answer
Oct 6, 2016

3(x+5/6)^2-49/12=y3(x+56)24912=y

Explanation:

The goal of completing the square is to convert the equation into a perfect square trinomial. The benefit of this form is to be able to identify the vertex of a parabola very easily.

Factor out a 3

3(x^2+5/3x)=23(x2+53x)=2

Take the coefficient from the x term and divide it by 2 and then square it.

((5/3)/2)^2=(5/3*1/2)^2=(5/6)^2=25/36(532)2=(5312)2=(56)2=2536

Include 25/362536 on the left and include 3(25/36)3(2536) on the right because we factored out a 3 on the left in an earlier step.

3(x^2+5/3x+25/36)=2+3(25/36)3(x2+53x+2536)=2+3(2536)

We now have a perfect square trinomial that can be written in a more compact form

3(x+5/6)^2=2+3(25/36)3(x+56)2=2+3(2536)

Simplify

3(x+5/6)^2=2+cancel3(25/(cancel36 12))

3(x+5/6)^2=2+(25/(12))

Convert 2 to 24/12 so that we have common denominator.

3(x+5/6)^2=24/12+(25/(12))

3(x+5/6)^2=49/12

Subtract 49/12

3(x+5/6)^2-49/12=0

3(x+5/6)^2-49/12=y

For more information please see the video tutorials below.