How do you solve $4^{12 - 3 x} = 64$ $4^(12-3x)=64$ ?

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Answer 1 · 2015-08-17T12:58:19

$x = 3$ $color(blue)(x=3$

$4^{12 - 3 x} = 64$ $4^(12-3x)=64$

We know that $64 = 4^{3}$ $64=4^3$

Rewriting the expression we obtain:
$4^{12 - 3 x} = 4^{3}$ $4^(12-3x)=4^3$

At this stage as bases are equal we equate the exponents to each other and find $x$ $x$
$12 - 3 x = 3$ $12-3x=3$

$12 - 3 = 3 x$ $12-3=3x$

$9 = 3 x$ $9=3x$

$x = 3$ $color(blue)(x=3$

How do you solve 412−3x=644^(12-3x)=64?