How do you solve $4.19 = - log x$ $4.19=-log x$ ?

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Answer 1 · 2016-01-07T05:08:08

Convert log to exponent form and solve. The solution is given below.

$4.19 = - log (x)$ $4.19 = -log(x)$
$- 4.19 = log (x)$ $-4.19=log(x)$
$log (x) = - 4.19$ $log(x) = -4.19$

Use the rule $log (x) = k \Rightarrow x = 10^{k}$ $color(brown) (log(x) =k => x=10^k$

$x = 10^{- 4.19}$ $x=10^(-4.19)$

How do you solve 4.19=−logx4.19=-log x?