Question

How do you solve `4^ { 3x - 9} - 10= - 3`?

Answer 1

`x = {log_4(7) + 9}/3 approx 4.4`

Explanation:

`4^{3x -9} - 10 = -3`

`4^{3x -9} = 7` //add 10 to both sides

`3x -9 = log_(4) 7` //`log_4` on both sides (`log_a(a^{x})=x`)

`3x = log_4(7) + 9` //add 9 to both sides

`x = {log_4(7) + 9}/3` //divide both sides by 3