How do you solve $4^{3 x - 9} - 10 = - 3$ $4^ { 3x - 9} - 10= - 3$ ?

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Answer 1 · 2018-03-28T07:04:39

$x = \frac{{log}_{4} (7) + 9}{3} \approx 4.4$ $x = {log_4(7) + 9}/3 approx 4.4$

$4^{3 x - 9} - 10 = - 3$ $4^{3x -9} - 10 = -3$

$4^{3 x - 9} = 7$ $4^{3x -9} = 7$ //add 10 to both sides

$3 x - 9 = {log}_{4} 7$ $3x -9 = log_(4) 7$ // ${log}_{4}$ $log_4$ on both sides ( ${log}_{a} (a^{x}) = x$ $log_a(a^{x})=x$ )

$3 x = {log}_{4} (7) + 9$ $3x = log_4(7) + 9$ //add 9 to both sides

$x = \frac{{log}_{4} (7) + 9}{3}$ $x = {log_4(7) + 9}/3$ //divide both sides by 3

How do you solve 43x−9−10=−34^ { 3x - 9} - 10= - 3?