How do you solve # 4 log_12 2 + log_12 x = log_12 96#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer VinÃcius Ferraz Dec 6, 2015 #{6}# Explanation: Unite the logs. #log_12 (2^4 * x) = log_12 96# #A = B Rightarrow 12^A = 12^B# #16 * x = 96# #x = 6# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 3159 views around the world You can reuse this answer Creative Commons License