Question

How do you solve `4e^(x - 1) = 64`?

Answer 1

We have that

`4*e^(x-1)=64`

`(4*e^(x-1))/4=64/4` (Divide by 4 both sides)

`e^(x-1)=16`

`(x-1)*lne=ln16` (Take logarithms in both sides)

`(x-1)=4*ln2` (Remember that `16=2^4`)

`x=1+4*ln2`