How do you solve $4 ln (2 x + 3) = 11$ $4ln(2x+3)=11$ ?

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Answer 1 · 2016-07-14T11:54:15

$x = 6.3213$ $x=6.3213$

As $4 ln (2 x + 3) = 11$ $4ln(2x+3)=11$ ,

$ln (2 x + 3) = \frac{11}{4} = 2.75$ $ln(2x+3)=11/4=2.75$ or

$2 x + 3 = e^{2.75} = 15.6426$ $2x+3=e^(2.75)=15.6426$ or

$2 x = 15.6426 - 3 = 12.6426$ $2x=15.6426-3=12.6426$ or

$x = \frac{12.6426}{2} = 6.3213$ $x=12.6426/2=6.3213$

How do you solve 4ln(2x+3)=114ln(2x+3)=11?