How do you solve $4 log x - 6 log (x + 2)$ $4log x - 6 log (x+2)$ ?

Question

5078 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-07-17T15:05:48

$log (\frac{x^{4}}{{(x + 2)}^{6}})$ $\log({x^4}/{(x+2)^6})$

Given that

$4 log x - 6 log (x + 2)$ $4\logx-6\log(x+2)$

$= 2 (2 log x - 3 log (x + 2))$ $=2(2\logx-3\log(x+2))$

$= 2 (log (x^{2}) - {log (x + 2)}^{3})$ $=2(\log(x^2)-\log(x+2)^3)$

$= 2 log (\frac{x^{2}}{{(x + 2)}^{3}})$ $=2\log({x^2}/{(x+2)^3})$

How do you solve 4logx−6log(x+2)4log x - 6 log (x+2)?