How do you solve $4 log x = \frac{log 1}{16}$ $4logx= log 1/16$ ?

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Answer 1 · 2016-04-21T19:13:37

$x = 1$ $x=1$

$log x = \frac{log 1}{64}$ $logx=log1/64$

$log x = \frac{0}{64}$ $log x =0/64$

$log x = 0$ $log x =0$

$10^{0} = x$ $10^0=x$

$x = 1$ $x=1$

How do you solve 4logx=log1164logx= log 1/16?