Question

How do you solve `4logx= log (1/16)`?

Answer 1

`x=1/2`

Explanation:

As `4logx=log(1/16)`

`logx^4=log(1/2^4)` or

`x^4=2^(-1xx4)=(2^(-1))^4`

Hence `x=2^(-1)` or `x=1/2`