How do you solve $4 x^{\frac{2}{3}} - 5 = 20$ $4x^(2/3) - 5 = 20$ ?

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Answer 1 · 2016-04-17T11:09:32

$x = \frac{125}{8}$ $x=125/8$

$4 x^{\frac{2}{3}} - 5 = 20$ $4x^(2/3)-5=20$

$4 x^{\frac{2}{3}} = 25$ $4x^(2/3)=25$

$x^{\frac{2}{3}} = \frac{25}{4}$ $x^(2/3)=25/4$

$x = {(\frac{25}{4})}^{\frac{3}{2}}$ $x=(25/4)^(3/2)$

$x = {(\frac{5^{2}}{2^{2}})}^{\frac{3}{2}}$ $x=(5^2/2^2)^(3/2)$

$x = {(\frac{5}{2})}^{3}$ $x=(5/2)^(3)$

$x = \frac{125}{8}$ $x=125/8$

How do you solve 4x23−5=204x^(2/3) - 5 = 20?