How do you solve -4x^2 +8x - 3 = 04x2+8x3=0 by completing the square?

1 Answer
Aug 31, 2016

Solution: x=3/2 or x=1/2x=32orx=12

Explanation:

-4x^2+8x-3=0 or -4(x^2-2x)-3=0 or -4(x^2-2x+1)+4-3=0 or -4(x-1)^2+1=0 or 4(x-1)^2=1 or (x-1)^2=1/4 or x-1= +-1/2 or x=1+1/2=3/2 or x= 1-1/2=1/2:.. Solution: x=3/2 or x=1/2[Ans]