How do you solve $4x^2-8x+57=0$ by completing the square?

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Answer 1 · 2016-04-06T16:23:21

No real roots

$y = 4x^2 - 8x + 57 = 0$
$D = b^2 - 4ac = 64 - 912 = - 848$
Since D < 9, there are no real roots. There are 2 complex roots.

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