How do you solve 4x - 2^(x+1) - 15 =0?

1 Answer
Cesareo R.
May 13, 2016

The equation has not real solution.

Explanation:

Consider the equation f = 4x-2^(x+1). This equation has a maximum for x = 1.5287 This poin is the critical point obtained solving (df)/dx = 4 - 2^(1 + x) Ln 2 = 0 giving x = Ln(4/Ln(2))/Ln(2)-1 = 1.52877. Substituting this value in f(1.52877) = 0.344285. This value is lower than 15 so no real solution is expected.

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