How do you solve 4x2x+115=0?

1 Answer
May 13, 2016

The equation has not real solution.

Explanation:

Consider the equation f=4x2x+1. This equation has a maximum for x=1.5287 This poin is the critical point obtained solving dfdx=421+xln2=0 giving x=ln(4ln(2))ln(2)1=1.52877. Substituting this value in f(1.52877)=0.344285. This value is lower than 15 so no real solution is expected.