How do you solve 4x - 3y = 22 4x3y=22 and 4x + 5y = 64x+5y=6?

1 Answer
Feb 16, 2017

y = -2y=2

x = 4x=4

Explanation:

Set it out in a column like so:

4x - 3y = 224x3y=22
4x + 5y = 64x+5y=6

Then subtract the second equation from the first one to get:

-8y = 168y=16

which can be simplified to

-y = 2" "y=2 or " "y = -2 y=2

This, in turn, can be used to work out the xx value:

4x -10 = 64x10=6

4x = 164x=16

x = 4x=4

Hopefully this helps...