Question

How do you solve `5.07^(t-1) = 100`?

Answer 1

`t = 1 + 2/log 5.07`=3.837, nearly.

Explanation:

`log a^m=m loga and log 10^n=n`

Equating logarithms,

`(t-1) log 5.07=log 100=log 10^2=2`
So, `t=1+2/log 5.07`.