Question

How do you solve `5(2^y)=3-(2^(y+2))`?

Answer 1

`y =-log_2 3`

Explanation:

`5times 2^y-3+4times2^y=0->9times 2^y-3=0`.

Applying logarithm to both sides

`y log_e 2=log_e(1/3)`.

Solving for `y`

`y = (log_e(1/3))/(log_e 2) = -log_2 3`