How do you solve #5^(2x+3)<=125#?

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Answer 1 · 2017-01-05T20:49:18

#x<=0#

Since #125=5^3#, the given inequality can be written as:

#5^(2x+3)<=5^3#

Then, since the base is less than 1, the inequality becomes:

#2x+cancel3<=cancel3#

that's

#2x<=0#

#x<=0#