How do you solve $5^{3 - 2 x} = 5^{- x}$ $5^(3-2x)=5^(-x)$ ?

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How do you solve $5^{3 - 2 x} = 5^{- x}$ $5^(3-2x)=5^(-x)$ ?

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Answer 1 · 2016-05-13T19:30:03

x = 3

Explanation:

Since the bases on both sides of the equation are 5 then the exponents must be equal.

If $a^{m} = a^{n} then m = n$ $a^m=a^n" then " m=n$

Equate the exponents and solve.

hence 3 - 2x = -x → -x = -3 → x = 3

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How do you solve $5^{3 - 2 x} = 5^{- x}$ $5^(3-2x)=5^(-x)$ ?

1 Answer

Explanation:

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