How do you solve #5^(3x + 2) = 25#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Alan P. Apr 9, 2016 #x=0# Explanation: #25=5^2# So #5^(3x+2) = 25# #color(white)("XXX")rarr 5^(3x+2)=5^2# #color(white)("XXX")rarr 3x+2=2# #color(white)("XXX")rarrx=0# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 3131 views around the world You can reuse this answer Creative Commons License