How do you solve $5^(n-1)=1/25$ ?

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Answer 1 · 2015-08-17T06:41:55

$color(blue)(n=-1$

$5^(n-1)=1/25$

$1/25=1/5^2$

As per property
$color(blue)(1/a=a^-1$

So, $1/5^2 = 5^-2$

$5^(n-1)=1/25$

$5^(n-1)=5^-2$
Since the bases are same we equate the exponents

$n-1=-2$

$color(blue)(n=-1$

How do you solve 5^(n-1)=1/25 5^(n-1)=1/25?