How do you solve #5^(n-3) = 1/25#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer A. S. Adikesavan Apr 7, 2016 n = 1 Explanation: #1/25=25\^(-1)=(5^2)^(-1)=5^(-2)#. Comparing with #5^(n-3), n-3=-2. So, n=1#. Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 1970 views around the world You can reuse this answer Creative Commons License