How do you solve $5^{n - 3} = \frac{1}{25}$ $5^(n-3)=1/25$ ?

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Answer 1 · 2017-01-17T11:08:58

$5^{n - 3} = \frac{1}{25} = 5^{- 2} \Rightarrow n - 3 = - 2 \Rightarrow n = 3 - 2 = 1 .$ $5^(n-3)=1/25=5^-2 rArr n-3=-2 rArr n=3-2=1.$

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