How do you solve $5^{x} = 3^{x}$ $5^x = 3^x$ ?

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Answer 1 · 2015-05-07T00:06:20

You could write it as:
$\frac{5^{x}}{3^{x}} = 1$ $5^x/3^x=1$
${(\frac{5}{3})}^{x} = 1$ $(5/3)^x=1$
That is possible when:
$x = 0$ $x=0$

How do you solve 5^x = 3^x5x=3x5^x = 3^x?