How do you solve $50=600e^(-0.4x)$ ?

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Answer 1 · 2016-01-19T00:46:25

First, isolate the exponential function ...

$50=600e^(-0.4x)$

$e^(0.4x)=12$

Now, take the natural log of both sides ...

$ln(e^(0.4x))=ln12$

$0.4x=ln12$

$x=(ln12)/0.4~~6.2123$

hope that helped!

How do you solve 50=600e^(-0.4x)50=600e^(-0.4x)?