How do you solve $\frac{500}{100 - e^{\frac{x}{2}}} = 20$ $500/(100-e^(x/2))=20$ ?

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Answer 1 · 2017-01-06T12:44:26

First, you get all of the constant terms on one side. Then you take the natural log of both sides.

$500 = 100−e^(x/2) * 20 ; 500 = 2000 – 20e^(x/2)$

$20e^(x/2) = 1500 ; e^(x/2) = 75$

$ln(e^(x/2)) = ln75 ; x/2 = 4.32 ; x = 8.64$

How do you solve 500/(100-e^(x/2))=20500100−ex2=20500/(100-e^(x/2))=20?