How do you solve $500 e^{- x} = 300$ $500e^-x=300$ ?

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Answer 1 · 2017-01-27T03:28:51

x= 0.5108

Divide by 500 on both sides,
$e^{- x} = \frac{3}{5}$ $e^(-x)= 3/5$

Therefore, $e^{x} = \frac{5}{3}$ $e^x=5/3$

Now take natural log on both sides,

x lne= ln 5- ln 3

x= ln 5 -ln 3 = 1.6094- 1.0986=0.5108

How do you solve 500e−x=300500e^-x=300?