How do you solve #5x^2-3x+7=7# by factoring?
2 Answers
Apr 13, 2018
Explanation:
Using the zero product property,
and
Apr 13, 2018
Explanation:
#"subtract 7 from both sides"#
#rArr5x^2-3x=0larrcolor(blue)"in standard form"#
#"take out a "color(blue)"common factor "x#
#rArrx(5x-3)=0#
#"equate each factor to zero and solve for x"#
#rArrx=0#
#5x-3=0rArrx=3/5#