Question

How do you solve `60,000 = 2^t`?

Answer 1

`t=(4+log 6)/log 2`

Explanation:

Equating logarithms,
log 60000=t log 2, using `log a^m=m log a`.
Use log ab = log a + log b and `log 10^N=N log _10 10= N X 1 = N`
So,
`t=(log 6 +log 10000)/log 2=(log 6 + log 10^4)/log 2=(log 6 + 4 )/log 2`..