How do you solve #600=10^x #?
1 Answer
Nov 21, 2015
Explanation:
#x = x log(10)#
#= log(10^x)#
#= log(600)#
#= log(100) + log(6)#
#= log(10^2) + log(6)#
#= 2+log(6)#
#= 2+log(2)+log(3)#
#~~ 2+0.30103+0.47712 = 2.77815#