How do you solve #66 + 8 log x = 50#?

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Answer 1 · 2015-12-19T23:19:39

#x=1/100#

Subtract #66# from both sides.

#8logx=-16#

Divide both sides by #8#.

#logx=-2#

Recall that #logx=log_10x#.

#log_10x=-2#.

Exponentiate both sides to undo the logarithm.

#10^(log_10x)=10^-2#

#x=10^-2#

#x=1/10^2=1/100#