How do you solve $66 + 8 log x = 50$ $66 + 8 log x = 50$ ?

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Answer 1 · 2015-12-19T23:19:39

$x = \frac{1}{100}$ $x=1/100$

Subtract $66$ $66$ from both sides.

$8 log x = - 16$ $8logx=-16$

Divide both sides by $8$ $8$ .

$log x = - 2$ $logx=-2$

Recall that $log x = {log}_{10} x$ $logx=log_10x$ .

${log}_{10} x = - 2$ $log_10x=-2$ .

Exponentiate both sides to undo the logarithm.

$10^{{log}_{10} x} = 10^{- 2}$ $10^(log_10x)=10^-2$

$x = 10^{- 2}$ $x=10^-2$

$x = \frac{1}{10^{2}} = \frac{1}{100}$ $x=1/10^2=1/100$

How do you solve 66+8logx=5066 + 8 log x = 50?