Question

How do you solve `6e^(9x)=1548`?

Answer 1

I found `x=0.617`

Explanation:

We can write it as:
`e^(9x)=1548/6`
`e^(9x)=258`
let us take the natural log of both sides:
`ln(e^(9x))=ln(258)`
`ln` and `e` eliminate each othe and we get:
`9x=ln(258)`
`x=(ln(258))/9=0.617`