How do you solve $6 x^{2} + 36 x + 18 = 0$ $6x^2 + 36x + 18 = 0$ using completing the square?

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How do you solve $6 x^{2} + 36 x + 18 = 0$ $6x^2 + 36x + 18 = 0$ using completing the square?

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Answer 1 · 2015-06-11T10:13:02

First thing to notice, is that everything can be divided by 6

Explanation:

So the equation becomes:
$x^{2} + 6 x + 3 = 0$ $x^2+6x+3=0$

Completing the square is you take half of the number with $x$ $x$ and square it, which would be $x^{2} + 6 x + 9$ $x^2+6x+9$ , but to even out with the $3$ $3$ you've got, you write $3 = 9 - 6$ $3=9-6$ :
$x^{2} + 6 x + 9 - 6 = 0 \to$ $x^2+6x+9-6=0->$
${(x + 3)}^{2} - 6 = 0 \to {(x + 3)}^{2} = 6 \to$ $(x+3)^2-6=0->(x+3)^2=6->$
$x + 3 = \pm \sqrt{6} \to x = - 3 \pm \sqrt{6}$ $x+3=+-sqrt6->x=-3+-sqrt6$

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How do you solve $6 x^{2} + 36 x + 18 = 0$ $6x^2 + 36x + 18 = 0$ using completing the square?

1 Answer

Explanation:

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How do you solve $6 x^{2} + 36 x + 18 = 0$ $6x^2 + 36x + 18 = 0$ using completing the square?