How do you solve # 7^(3x+1) = 270#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer mason m Dec 13, 2015 #x=(log_7 270-1)/3# Explanation: Take the #log_7# of both sides. #log_7(7^(3x+1))=log_7 270# #3x+1=log_7 270# #3x=Log_7 270-1# #x=(log_7 270-1)/3# #x~~0.626# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 1357 views around the world You can reuse this answer Creative Commons License