How do you solve $7^{3 x + 1} = 270$ $7^(3x+1) = 270$ ?

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Answer 1 · 2015-12-13T21:17:08

$x = \frac{{log}_{7} 270 - 1}{3}$ $x=(log_7 270-1)/3$

Take the ${log}_{7}$ $log_7$ of both sides.

${log}_{7} (7^{3 x + 1}) = {log}_{7} 270$ $log_7(7^(3x+1))=log_7 270$

$3 x + 1 = {log}_{7} 270$ $3x+1=log_7 270$

$3 x = {log}_{7} 270 - 1$ $3x=Log_7 270-1$

$x = \frac{{log}_{7} 270 - 1}{3}$ $x=(log_7 270-1)/3$

$x \approx 0.626$ $x~~0.626$

How do you solve 73x+1=270 7^(3x+1) = 270?