How do you solve $- 7 + ln 2 x = 4$ $-7 + ln 2x =4$ ?

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How do you solve $- 7 + ln 2 x = 4$ $-7 + ln 2x =4$ ?

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Answer 1 · 2016-02-23T22:24:08

$x = \frac{1}{2} \cdot e^{11}$ $x=1/2*e^11$

Explanation:

from the given $- 7 + ln 2 x = 4$ $-7+ln 2x=4$
transpose -7 to the right of the equation

$ln 2 x = 4 + 7$ $ln 2x=4+7$

simplify

$ln 2 x = 11$ $ln 2x=11$

this is also

${ln}_{e} 2 x = 11$ $ln_e 2x=11$

convert to exponential form

$e^{11} = 2 x$ $e^11=2x$

divide both sides of the equation by 2

$x = \frac{1}{2} \cdot e^{11}$ $x=1/2*e^11$

Do the checking at $x = \frac{1}{2} \cdot e^{11}$ $x=1/2*e^11$ using the original equation

$- 7 + ln 2 x = 4$ $-7+ln 2x=4$
$- 7 + ln 2 (\frac{1}{2} \cdot e^{11}) = 4$ $-7+ln 2(1/2*e^11)=4$
$- 7 + {ln e}^{11} = 4$ $-7+ln e^11=4$
$- 7 + 11 = 4$ $-7+11=4$
$4 = 4$ $4=4$ correct !!!

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How do you solve $- 7 + ln 2 x = 4$ $-7 + ln 2x =4$ ?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

How do you solve −7+ln2x=4-7 + ln 2x =4?

1 Answer

Explanation:

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How do you solve $- 7 + ln 2 x = 4$ $-7 + ln 2x =4$ ?