How do you solve #-7 + ln 2x =4#?

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Answer 1 · 2016-02-23T22:24:08

#x=1/2*e^11#

from the given #-7+ln 2x=4#
transpose -7 to the right of the equation

#ln 2x=4+7#

simplify

#ln 2x=11#

this is also

#ln_e 2x=11#

convert to exponential form

#e^11=2x#

divide both sides of the equation by 2

#x=1/2*e^11#

Do the checking at #x=1/2*e^11# using the original equation

#-7+ln 2x=4#
#-7+ln 2(1/2*e^11)=4#
#-7+ln e^11=4#
#-7+11=4#
#4=4# correct !!!

God bless you ...