How do you solve $7^x=1/49$ ?

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Answer 1 · 2017-11-20T10:06:16

By arranging the equation

$7^x = 1/49 = 1/(7^2)$

$(7^x)times(7^2)=1$

zeroth power of any number is 1.

$x+2 = 0$

$x=-2$

This is your answer $x=-2$

How do you solve 7^x=1/497^x=1/49?