How do you solve $7^{x} = 30$ $7^x = 30$ ?

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Answer 1 · 2016-04-08T07:14:29

$x = 1.7478$ $x=1.7478$

$7^{x} = 30$ $7^x=30$ means $x = {log}_{7} (30)$ $x=log_7(30)$ .

$x = {log}_{7} (30) = \frac{log 30}{log 7} = \frac{1.4771}{0.8451} = 1.7478$ $x=log_7(30)=log30/log7=1.4771/0.8451=1.7478$

How do you solve 7^x = 307x=307^x = 30?