How do you solve $8^{- \frac{1}{3}} = \frac{1}{2}$ $8^(-1/3) = 1/2$ ?

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How do you solve $8^{- \frac{1}{3}} = \frac{1}{2}$ $8^(-1/3) = 1/2$ ?

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Answer 1 · 2016-05-29T18:35:09

This statement is true. There is no variable to solve for.

Explanation:

This is a true statement and has no variable to be solved for.

note that $8^{- \frac{1}{3}} = \frac{1}{8^{\frac{1}{3}}} = \frac{1}{\sqrt[3]{8}} = \frac{1}{2}$ $8^(-1/3)=1/8^(1/3)=1/root(3)(8)=1/2$

Using $rules of indices$ $color(blue)"rules of indices"$

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How do you solve $8^{- \frac{1}{3}} = \frac{1}{2}$ $8^(-1/3) = 1/2$ ?

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How do you solve $8^{- \frac{1}{3}} = \frac{1}{2}$ $8^(-1/3) = 1/2$ ?