How do you solve $8(10^(3x))=12$ ?

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Answer 1 · 2017-02-04T15:20:25

$x=0.0587$ .

We will use the familiar rules of Log function.

$8(10^(3x))=12$

$rArr 10^(3x)=12/8=3/2$ .

$rArr log_10 10^(3x)=log_10 (3/2)=log_10 3- log_10 2$ .

$rArr (3x)log_10 10=0.4771-0.3010=0.1761.$

$rArr 3x=0.1761$ .

$rArr x=0.1761/3$ .

$:." The Soln. is, "x=0.0587$ .

How do you solve 8(10^(3x))=128(10^(3x))=12?